From an upper bound on sqrt_two_add_series 0 n = 2 cos (pi / 2 ^ (n+1))
of the form
sqrt_two_add_series 0 n ≤ 2 - (a / 2 ^ (n + 1)) ^ 2)
, one can deduce the lower bound a < pi
thanks to basic trigonometric inequalities as expressed in pi_gt_sqrt_two_add_series
.
Create a proof of a < pi
for a fixed rational number a
, given a witness, which is a
sequence of rational numbers sqrt 2 < r 1 < r 2 < ... < r n < 2
satisfying the property that
sqrt (2 + r i) ≤ r(i+1)
, where r 0 = 0
and sqrt (2 - r n) ≥ a/2^(n+1)
.
From a lower bound on sqrt_two_add_series 0 n = 2 cos (pi / 2 ^ (n+1))
of the form
2 - ((a - 1 / 4 ^ n) / 2 ^ (n + 1)) ^ 2 ≤ sqrt_two_add_series 0 n
, one can deduce the upper bound
pi < a
thanks to basic trigonometric formulas as expressed in pi_lt_sqrt_two_add_series
.
Create a proof of pi < a
for a fixed rational number a
, given a witness, which is a
sequence of rational numbers sqrt 2 < r 1 < r 2 < ... < r n < 2
satisfying the property that
sqrt (2 + r i) ≥ r(i+1)
, where r 0 = 0
and sqrt (2 - r n) ≥ (a - 1/4^n) / 2^(n+1)
.